0=4.9t^2+8t-600

Solution for 0=4.9t^2+8t-600 equation:

0=4.9t^2+8t-600

We move all terms to the left:

0-(4.9t^2+8t-600)=0

We add all the numbers together, and all the variables

-(4.9t^2+8t-600)=0

We get rid of parentheses

-4.9t^2-8t+600=0

a = -4.9; b = -8; c = +600;
Δ = b2-4ac
Δ = -82-4·(-4.9)·600
Δ = 11824
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{11824}=\sqrt{16*739}=\sqrt{16}*\sqrt{739}=4\sqrt{739}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-4\sqrt{739}}{2*-4.9}=\frac{8-4\sqrt{739}}{-9.8}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+4\sqrt{739}}{2*-4.9}=\frac{8+4\sqrt{739}}{-9.8}
$